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Post Info TOPIC: Aerodynamic Transmission


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Aerodynamic Transmission
 


I would like to jump in and join this great discussion if I may be allowed.

Aerodynmic transmission is the only way to achieve higher efficiencies, IMHO...

That being said, all of you have touched on what I have percieved as a more systemic approach to the Betz limit.

It is best to see my perspective from this comparison and analogy;

The typicaly termed HAWT has a large blade rotating at high tip velocity at its peak output. Some propose the tip velocity ratio is what gives the VAWT an advantage in terms of maximum Cp transfer. That's not how I see it at all. I see the velocity ratio (or velocity disparity, as I call it) is its limitation of appropriate inertial possession, in relation to magnitude of velocity. That is where the transmission breaks down. Centrifigul force is held in tighter radions more or less if you want to term it in such a way... but because of structural considerations these areas must contain higher inertias than ideal. They are also the pathway of the energy transmission to the shaft.

 

The generaly termed HAWT has a more inherent problem. Varying angle of attack and opposite drag forces that cancel out the lift factor. It's almost unavoidable without a greater construct... as seen in the ouput Cp's.

Now, working under the Betz limit is the key, in one area to the next... if you get what I mean. If not, allow me to elaborate... The V1 to V2 ratios are at given system pressures, now if those system pressures were different, then the P ratios become farther apart in terms of kinetic transfer. Pressure differentials drive the systems, not the other way around. You can't have an increase in velocity without a pressure differential, the greater the pressure differential the greater the rate of acceleration. Now you ask how can we change static pressures in a HAWT? The answer is simple, you can change static pressures with dynamic force greater than the static pressure system. Or in otherwords we need to create a low pressure area or (vaccuum pressence) on the opposit end of the HAWT in question... That is the begining.

Next this systems energy transfer system has to do so with little drag. Drag is the enemy and I will explain why. All this comes together now...

I would like everyone to picture a big rock in a stream that's moving at a slow pace that is upstream from a water fall. In front of the rock the parting line of where the water passes around the rock is relatively close to the rock. you can begin to see a eddy current develop behind the rock. a slight swirly but nothing major. Farther down stream there is a smaller rock but the stream is moving faster and here you can see the front parting area where the stream splits actualy extends farther out than the previous rock and here the eddy current at the rear is becoming more pronounced. Lastly there is an even smaller rock right before the waterfall. The last rock is smaller yet but the split path of the water is way more pronounced, extending upstream many times the rocks size and the eddy current has developed into a wild spinning vertice of terror before it plummets off the cliff.

From this visual perspective I would like you guys to try and see that the size, shape or mass of the stream doesn't change but the velocity of the water increased as it approached the waterfall. Inertia is propogated through the medium from the point of low inertia to high inertia, but it wasn't because a change in volume (as the conservation of mass presumes) but yet it is a system transfer of power from a greater dynamic pressence in the system, in this case gravity.

Now what if the rocks stayed all big and huge to the point of slowing the stream down to the point of moving real slow until it reached the waterfall? You would see the water would not have as large of a fall crest off the cliff because it had less inertia because the rocks created so much drag. Even though the gravitational force was constant, the drag reluted in a loss of kinetic energy.

Anyone see where I am going with this?

View the formost part of a wing, or the rocks in the stream as in this case, as entities that creates dynamic compression within the fluid stream. Greater the velocity of the medium, the greater the compressive load can become at a given mass density for a given volumetric displacement. Now due to increases in inertial load the force increases to create flow restrictions (drag), that lower the overall power transfer capability of the system if these forces aren't brought to a minumum then the sytem will not be efficient.

Thoughts anyone?



-- Edited by gtfoxy on Wednesday 19th of December 2012 06:02:01 PM

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RE: Aerodynamic Transmission
 


I've been straining my brain for the past few days figuring out the efficiency of an Aerodynamic Transmission and I believe I have found the answer.  I actually got this answer 2 different ways.  I didn't believe it the first time so I took a different approach and arrived at the same point.

In short, an Aerodynamic transmission is between 50% and 100% efficient.  The 50% end of the scale isn't realistic because the math breaks down in exactly the same way that the Betz limit equations predict that a solid wall is 50% efficient.

Given an AT moving at velocity V1 through still air, and the air behind the AT is accelerated to V2 the efficiency of the AT is

(2*V1 - V2) / 2V1       You wouldn't believe how complex those equations were before everything simplified out!

So first off some of you are saying, it can't be 100% efficient because of the Betz limit.   The confusing thing is we are talking about 2 different types of efficiency.   Betz tells us what percentage of the power in the moving air we can extract.    That efficiency drops because some of the air goes around the turbine.   The limit I found (Lets just call it the AT Limit) is the percentage of power you can extract of the power needed to push the AT through the air.  If the air goes around, it becomes slightly easier to push, so that air matters less.

Now, Peter before you open the campaign and start to celebrate that you can have a 100% AT efficiency, I need to tell you that physics always gets you.

So what's the catch?????   Well, looking at the equation, the 100% efficiency comes in when V2 is 0.  In other words you dragged something through the air that didn't move the air at all.  If you extract no power, then you are 100% efficient.   That's not very useful.

Lets take the case where the AT is at the Betz limit for extracting the energy from the virtual wind it sees.  In that case V2/V1 = 2/3.   The efficiency of the AT (extracted / pushed) = (6-2)/6 = 4/6 = 2/3 = 66% efficient.  Note that really is power out / power in so it's not necessary to multiply by the 59% Betz limit.  That's already in there.  Now if you use a bad blade or make a turbine that can't turn, you can still cause your efficiency to drop toward zero.

One other interesting thing about this equation is it says you'd be better off if you could make your AT oversized and run it below the Betz limit.   Then your efficiency can go higher.  Of course there is a limit to how big an AT can get when it's mounted on a wing.

Lets take the case where the air behind is moving 1/3rd the speed of the AT.  In that case we are 83% efficient and the AT can still extract about 45% of the power in the wind it sees.

Anyway, I think this shows there is hope for the Aerodynamic transmission idea.  If anyone wants to see the math let me know, and I will post it.  Otherwise I won't bother.

 

 

 

 

 



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Steve


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RE: Aerodynamic Transmission
 


crazyguy wrote:

http://www.youtube.com/watch?v=5CcgmpBGSCI


 This is the downwind run with the wheels driving the propeller. At first the drag on the prop starts blowing the car downwind, as the wheels turn they drive the prop to blow against the wind making the car go faster than the wind.

The car was later modified by replacing the prop with a turbine to drive the wheels to run into the wind.



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Dan


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RE: Aerodynamic Transmission
 


http://www.youtube.com/watch?v=5CcgmpBGSCI



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Aerodynamic Transmission
 


 

sjh7132 wrote:


PASVAWT wrote:
Here's an interesting bit of information to think about: The amazing Blackbird windmill-driven land yacht achieved a speed directly into the wind of 2 times the wind speed. It fed its own power into the wheels to drive it forward. That is partially analogous to a VAWT driving an AT forward. What is especially interesting is that to do that, the Blackbird's windmill has to operate at reduced power so as to achieve the best lift to drag ratio for the blades, and thereby minimize the rotor drag.

 That thought had crossed my mind..... Is there an operating point where the AT is not close to Betz and it has much less drag so that the power to drag ratio is lower and it's more efficient?  It sounds like that might be the case.  If I get bored late tonight I'll see if I can calculate thinking that way.

 


 I just checked to make sure. The Blackbird is a downwind vehicle that uses wheel power to drive a propeller.

Oops. I just found this for the modified blackbird.

http://www.nalsa.org/BlackBirdDDWSR/UpwindSubmisionReportNALSA.pdf



-- Edited by fluitic on Thursday 13th of December 2012 10:02:25 PM

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Dan


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RE: Aerodynamic Transmission
 


PASVAWT wrote:
Here's an interesting bit of information to think about: The amazing Blackbird windmill-driven land yacht achieved a speed directly into the wind of 2 times the wind speed. It fed its own power into the wheels to drive it forward. That is partially analogous to a VAWT driving an AT forward. What is especially interesting is that to do that, the Blackbird's windmill has to operate at reduced power so as to achieve the best lift to drag ratio for the blades, and thereby minimize the rotor drag.

 That thought had crossed my mind..... Is there an operating point where the AT is not close to Betz and it has much less drag so that the power to drag ratio is lower and it's more efficient?  It sounds like that might be the case.  If I get bored late tonight I'll see if I can calculate thinking that way.

 



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Steve


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RE: Aerodynamic Transmission
 


sjh7132 wrote:
PASVAWT wrote:

My understanding of what that 80% maximum means is that the combination would be equal to 59.3 times .80, or 47.44 maximum efficiency. If a practical efficiency of 50% for the AT is used, then the actually efficiency would be roughly 40% times 50%, or 20% of the energy passing through the VAWT.


 Ah then there is a difference in how we even define efficiency.  My definiation is what percent of the power put into moving the aerodynamic transmission comes out as electricity.  So it's a percentage of total power in, not of the Betz limit.   So really we are comparing my 30% against 47% which is a lot closer.

 


 Hi Steve,

I think that we are saying the same thing but assuming different efficiencies for the AT.

My understanding is that an AT can capture and transmit only 80% of the power being produced by the VAWT, and that is the theoretical limit for the AT, not the practical limit, which would be much lower.

However, I don't think that the Betz limit applies to the AT. That is because the AT can bring the air passing through it to a complete stop, and air will still flow through the AT -- because the AT is moving away from the air behind it. Where an AT would become inefficient is if it starts pulling air along behind it. But as we've discussed, the true wind will be acting on the air behind the AT most of the time and sweeping it away. So that should help a lot. But how to calculate all those effects is far beyond me.

A very efficient computer controlled cycloturbine operating at, say, 55% efficiency combined with a very efficient AT operating at, say, 60% efficiency, would give a combined efficiency of 33%. That should be possible some day. But probably not soon. I'm going to stick with a likely combined practical efficiency of about 20%, and focus on cuttng costs so as to maximize the swept area.That assumes that the AT will achieve a 50% efficiency, and the VAWt will achieve a 40% efficiency. That seems reasonably conservative.

And if the VAWT achieves only 20% efficiency, then the combined efficiency will be only 10%. That might be the case for a single-blade Bird Windmill equipped with an AT mounted on the blade (on the rocking axis so as to not affect blade pitching).

Here's an interesting bit of information to think about: The amazing Blackbird windmill-driven land yacht achieved a speed directly into the wind of 2 times the wind speed. It fed its own power into the wheels to drive it forward. That is partially analogous to a VAWT driving an AT forward. What is especially interesting is that to do that, the Blackbird's windmill has to operate at reduced power so as to achieve the best lift to drag ratio for the blades, and thereby minimize the rotor drag.

An ordinary efficient windmill has a hard time going faster than about half the speed of the wind when heading directly upwind.

The 6 part video lecture by Mac Gaunaa, et. al. on the subject of using a rotor to sail directly upwind and directly down wind faster than the wind may be relevant to how to optimize an AT. It may need to minimize its drag in order to maximize its power. But I'm just guessing.

(Incidentally, the basic concepts in that lecture are ones that I published 6 years before he did. But he did the math, which I could not. On the other hand, I showed that, by moving to a higher level of abstraction, one equation could be used to describe both situations -- whereas he used separate equations.)



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Peter A. Sharp


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RE: Aerodynamic Transmission
 


PASVAWT wrote:

My understanding of what that 80% maximum means is that the combination would be equal to 59.3 times .80, or 47.44 maximum efficiency. If a practical efficiency of 50% for the AT is used, then the actually efficiency would be roughly 40% times 50%, or 20% of the energy passing through the VAWT.


 Ah then there is a difference in how we even define efficiency.  My definiation is what percent of the power put into moving the aerodynamic transmission comes out as electricity.  So it's a percentage of total power in, not of the Betz limit.   So really we are comparing my 30% against 47% which is a lot closer.

 



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Steve


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RE: Aerodynamic Transmission
 


My understanding of what that 80% maximum means is that the combination would be equal to 59.3 times .80, or 47.44 maximum efficiency. If a practical efficiency of 50% for the AT is used, then the actually efficiency would be roughly 40% times 50%, or 20% of the energy passing through the VAWT.

If this is true, then to be practical, the swept area would need to be especially large. Power generating kites do achieve an extremely large swept area relative to the size of the blade. The Bird Windmill does too, although not nearly as large as power generating kites, because the TSR is only 2, whereas the kites probably operate at a TSR of around 6 or even more.

Kites have a further advantage in that they are higher where the winds blow stronger and more often. They have a high capacity factor.

However, the Bird Windmill is potentially much cheaper than the kites because it requires no complex controls. And the AT should be much smaller and cheaper than a conventional generator. 

The VAWT would be over-sized with a low solidity ratio so as to provide clean air to the AT for as much of the time as possible -- down wind as well as up wind.

Under those circumstances, a VAWT equipped with an AT might work.

The technique can be reversed, conceptually. Think of the small HAWT as the wind turbine. Think of the large VAWT as a wind concentrator. The concentration ratio is much higher than can be achieved by shrouds or other concentrating devices. But the VAWT must be very cheap and very large in order to be practical. The Bird Windmill satisfies that requirement. But it's too soon to be sure the combination would work technically. I think it can, but I still need to test it.



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Peter A. Sharp


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Aerodynamic Transmission
 


Steve made a joke!!!!!!!!!!!

I think I've died and seen the gates!!

HAHAHAHA

I think the AT is probably less efficient than even your estimate  because of the economies of scale and the losses that are experienced when you devide the work up amongst all the little units. I also think Betz law still comes into effect when you consider the blockage the unit as a whole will create in the airflow.



-- Edited by itsandbits1 on Monday 10th of December 2012 02:50:17 PM

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